源码
今天调试了一下golang编译工具,发现了一个很有"奇怪"的地方
简化问题
假设有1000个任务,1000个并发协程,设置n(cpu核数)个物理处理器(task)并发完成,每个协程只要完成了当前任务采取完成下一个
代码
原始代码,go作者无所畏惧的使用协程
func parseFiles(filenames []string) uint {
var noders []*noder
// Limit the number of simultaneously open files.
sem := make(chan struct{}, runtime.GOMAXPROCS(0)+10)
for _, filename := range filenames {
go func(filename string) {
sem <- struct{}{}
defer func() { <-sem }()
...
}(filename)
}
针对问题代码
package main
import (
"fmt"
"math/rand"
"os"
"os/signal"
"runtime"
"time"
)
func main() {
c := make(chan os.Signal)
signal.Notify(c, os.Interrupt)
rand.Seed(time.Now().UnixNano())
task := make([]func(), 1000)
for i := 0; i < 1000; i++ {
task[i] = func() {
r := rand.Intn(100)
time.Sleep(time.Duration(r) * time.Millisecond)
fmt.Printf("Task cost %d\n", r)
}
}
sem := make(chan struct{}, runtime.GOMAXPROCS(0)+10)
for i := 0; i < len(task); i++ {
f := task[i]
go func(f func()) {
sem <- struct{}{}
defer func() { <-sem }()
f()
}(f)
}
<-c
}
如果控制10个协程,应该怎么写呢
package main
import (
"fmt"
"math/rand"
"os"
"os/signal"
"runtime"
"sync"
"time"
)
func main() {
c := make(chan os.Signal)
signal.Notify(c, os.Interrupt)
exit := make(chan bool)
sem := make(chan func(), runtime.GOMAXPROCS(0))
task := make([]func(), 1000, 1000)
rand.Seed(time.Now().UnixNano())
for i := 0; i < len(task); i++ {
task[i] = func() {
r := rand.Intn(100)
time.Sleep(time.Duration(r) * time.Millisecond)
fmt.Printf("task cost %d\n", r)
}
}
wg := &sync.WaitGroup{}
for i := 0; i < runtime.GOMAXPROCS(0); i++ {
wg.Add(1)
go func() {
defer wg.Done()
for {
select {
case f := <-sem:
f()
case <-exit:
fmt.Printf("Gracefully exit....\n")
return
}
}
}()
}
go func() {
for i := 0; i < len(task); i++ {
sem <- task[i]
}
}()
<-c
close(exit)
wg.Wait()
}